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प्रश्न
If log10 a = b, find 103b - 2 in terms of a.
उत्तर
log10 a = b
⇒ 10b = a
⇒ ( 10b )3 = a3 ...[ Cubing both sides ]
⇒ `10^(3b)/10^2 = a^3/10^2` ...[dividing both sides by 102]
⇒ 103b - 2 = `a^3/100`
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