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प्रश्न
If log10 a = b, find 103b - 2 in terms of a.
उत्तर
log10 a = b
⇒ 10b = a
⇒ ( 10b )3 = a3 ...[ Cubing both sides ]
⇒ `10^(3b)/10^2 = a^3/10^2` ...[dividing both sides by 102]
⇒ 103b - 2 = `a^3/100`
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संबंधित प्रश्न
Given 2 log10 x + 1 = log10 250, find :
(i) x
(ii) log10 2x
Prove that:
log10 125 = 3(1 - log102).
Simplify : log (a)3 - log a
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Write the logarithmic equation for:
F = `"G"("m"_1"m"_2)/"d"^2`
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V = `(4)/(3)pi"r"^3`
If log 16 = a, log 9 = b and log 5 = c, evaluate the following in terms of a, b, c: log 2.25
If log x = p + q and log y = p - q, find the value of log `(10x)/y^2` in terms of p and q.
If log a = p and log b = q, express `"a"^3/"b"^2` in terms of p and q.
Find the value of:
`("log"sqrt125 - "log"sqrt(27) - "log"sqrt(8))/("log"6 - "log"5)`
