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Find the Value Of: Log √ 125 − Log √ 27 − Log √ 8 Log 6 − Log 5 - Mathematics

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प्रश्न

Find the value of:

`("log"sqrt125 - "log"sqrt(27) - "log"sqrt(8))/("log"6 - "log"5)`

योग

उत्तर

`("log"sqrt125 - "log"sqrt(27) - "log"sqrt(8))/("log"6 - "log"5)`

= `("log"(125)^(1/2) - "log"(27)^(1/2) - "log"(8)^(1/2))/("log"6 - "log"5)`

= `("log"(5)^(3xx1/2) - "log"(3)^(3xx1/2) - "log"(2)^(3xx1/2))/("log"6 - "log"5)`

= `(3/2 "log"(5) - 3/2"log"(3) - 3/2"log"(2))/("log"(2 xx 3) - "log"5)`

= `(3/2["log"(5) - "log"(3) - "log"(2)])/("log"2 + "log"3 - "log"5)`

= `(3/2["log"(5) - "log"(3) - "log"(2)])/(-["log"5 - "log"3 - "log"2])`

= `-(3)/(2)`.

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Expansion of Expressions with the Help of Laws of Logarithm
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Logarithms - Exercise 10.2

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 10 Logarithms
Exercise 10.2 | Q 32.3
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