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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

If OAaandOBbOA¯=a¯andOB¯=b¯, then show that the vector along the angle bisector of ∠AOB is given by daabbd¯=λ(a¯|a¯|+b¯|b¯|). - Mathematics and Statistics

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प्रश्न

If `bar"OA" = bar"a" and bar"OB" = bar"b",` then show that the vector along the angle bisector of ∠AOB is given by `bar"d" = lambda(bar"a"/|bar"a"| + bar"b"/|bar"b"|).`

बेरीज

उत्तर

Choose any point P on the angle bisector of ∠AOB. Draw PM parallel to OB.

∴ ∠OPM = ∠POM = ∠POB

Hence, OM = MP

∴ OM and MP is the same scalar multiple of unit vectors `hat"a" and hat"b"` along these directions,

where `hat"a" = bar"a"/|bar"a"| and hat"b" = bar"b"/|bar"b"|`

∴ `bar"OM" = lambdahat"a" and bar"MP" = lambdahat"b"`

∴ `bar"OP" = bar"OM" + bar"MP"`

`= lambdahat"a" + lambdahat"b"`

`= lambda(hat"a" + hat"b")`

Hence, the vector along angle bisector of ∠AOB is given by

`bar"d" = bar"OP" = lambda(bar"a"/|bar"a"| + bar"b"/|bar"b"|)`.

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पाठ 5: Vectors - Miscellaneous exercise 5 [पृष्ठ १९०]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 12 Standard HSC Maharashtra State Board
पाठ 5 Vectors
Miscellaneous exercise 5 | Q II. 13) | पृष्ठ १९०

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