Advertisements
Advertisements
प्रश्न
If the quadratic equation px2 − 2√5px + 15 = 0 has two equal roots then find the value of p.
उत्तर
- a = p
- b = `-2sqrt5p`
- c = 15
Δ = b2 − 4ac
`(−2sqrt5p)^2−4(p)(15)=0`
`(2sqrt5p)^2 - 60p = 0`
4 × 5p2 − 60p = 0
20p2 − 60p = 0
20p(p − 3) = 0
p = 0 or p = 3
Since p = 0 would make the equation invalid, we take:
p = 3
APPEARS IN
संबंधित प्रश्न
Determine the nature of the roots of the following quadratic equation :
2x2 + x-1=0
In each of the following determine the; value of k for which the given value is a solution of the equation:
x2 + 2ax - k = 0; x = - a.
Find the value of k so that sum of the roots of the quadratic equation is equal to the product of the roots:
(k + 1)x2 + (2k + 1)x - 9 = 0, k + 1 ≠ 0.
If b2 – 4ac > 0 and b2 – 4ac < 0, then write the nature of roots of the quadratic equation for each given case
The sum of the roots of the quadratic equation 3x2 – 9x + 5 = 0 is:
If (1 – p) is a root of the equation x2 + px + 1 – p = 0, then roots are:
(x2 + 1)2 – x2 = 0 has:
Find the roots of the quadratic equation by using the quadratic formula in the following:
–3x2 + 5x + 12 = 0
State whether the following quadratic equation have two distinct real roots. Justify your answer.
`(x - sqrt(2))^2 - 2(x + 1) = 0`
If α and β be the roots of the equation x2 – 2x + 2 = 0, then the least value of n for which `(α/β)^n` = 1 is ______.