Advertisements
Advertisements
प्रश्न
If the sum of first n terms of an AP is n2, then find its 10th term.
उत्तर
We know sum of n terms of an AP is
Sn = n2
For n = 1, S1 = (1)2 = 1
So, a1 = 1
For n = 2, S2 = (2)2 = 4
For n = 3, S3 = (3)2 = 9
S2 - S1 = a2
⇒ a2 = 4 - 1 = 3
So, d = a2 - a1 = 3 - 1 = 2
We knopw nth term of an AP is
an = a + (n-1)d
For n = 10
a10 = 1+ (10 - 1)2
⇒ a10 = 1+ 9 × 2
⇒ a10 = 19
Thus, the 10th term of the AP is 19.
APPEARS IN
संबंधित प्रश्न
Find the sum of the following arithmetic series:
34 + 32 + 30 +...+10
Find the sum of the following arithmetic series:
(-5)+(-8)+(-11)+...+(-230)
Six year before, the age of mother was equal to the square of her son's age. Three year hence, her age will be thrice the age of her son then. Find the present ages of the mother and son.
Find the 23rd term of the following A.P.: 9, 4,-1,-6,-11.
Find t5 if a = 3 आणि d = −3
Decide whether the given sequence 24, 17, 10, 3, ...... is an A.P.? If yes find its common term (tn)
Decide whether 301 is term of given sequence 5, 11, 17, 23, .....
Activity :- Here, d = `square`, therefore this sequence is an A.P.
a = 5, d = `square`
Let nth term of this A.P. be 301
tn = a + (n – 1) `square`
301 = 5 + (n – 1) × `square`
301 = 6n – 1
n = `302/6` = `square`
But n is not positive integer.
Therefore, 301 is `square` the term of sequence 5, 11, 17, 23, ......
If tn = 2n – 5 is the nth term of an A.P., then find its first five terms
The nth term of an A.P. 5, 8, 11, 14, ...... is 68. Find n = ?
Write the next two terms of the A.P.: `sqrt(27), sqrt(48), sqrt(75)`......