Advertisements
Advertisements
प्रश्न
Write the next two terms of the A.P.: `sqrt(27), sqrt(48), sqrt(75)`......
उत्तर
Given A.P. is `sqrt(27), sqrt(48), sqrt(75)` ......
Here, a1 = `sqrt(27) = 3sqrt(3)`
a2 = `sqrt(48) = 4sqrt(3)`
∴ Common difference = `4sqrt(3) - 3sqrt(3)`
= `sqrt(3) (4 - 3) = sqrt(3)`
Now, Given a3 = `sqrt(75) = 5sqrt(3)`
∴ a4 = `6sqrt(3) = sqrt(108)`
And a5 = `7sqrt(3) = sqrt(147)`
Hence, next two terms are `sqrt(108)` and `sqrt(147)`.
संबंधित प्रश्न
If the 9th term of an A.P. is zero, then prove that 29th term is double of 19th term.
Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression.
Find the 27th term of the following A.P.
9, 4, –1, –6, –11,...
Select the correct alternative and write it.
What is the sum of first n natural numbers ?
Select the correct alternative and write it.
If a share is at premium, then -
Find the 23rd term of the following A.P.: 9, 4,-1,-6,-11.
If the sum of first n terms of an AP is n2, then find its 10th term.
Find tn if a = 20 आणि d = 3
Decide whether the given sequence 24, 17, 10, 3, ...... is an A.P.? If yes find its common term (tn)
Find a and b so that the numbers a, 7, b, 23 are in A.P.
