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प्रश्न
Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression.
उत्तर
The given sequence is 12, 16, 20, 24, . . .
Here,
First term (a) = 12
Common difference (d) = a2 – a1 = 16 – (12) = 4
Now,
\[a_{24} = a + \left( n - 1 \right)d\]
\[ = 12 + \left( 24 - 1 \right)4\]
\[ = 12 + \left( 23 \right)4\]
\[ = 104\]
Hence, the 24th term of the progression is 104.
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