Advertisements
Advertisements
प्रश्न
If three quantities are in continued proportion, show that the ratio of the first to the third is the duplicate ratio of the first to the second.
उत्तर
Let x, y and z are the three quantities which are in continued proportion
Then, x : y :: y : z => y2 = xz
Now, we have to prove that
x : z = x2 : y2
⇒ xy2 = x2z
LHS
= xy2 = x(xz) = x2z = RHS
LHS = RHS
APPEARS IN
संबंधित प्रश्न
Check whether the following numbers are in continued proportion.
1, 2, 3
If y is the mean proportional between x and z, show that :
xyz (x+y+z)3 =(xy+yz+xz)3
If `a/b = c/d = e/f`, prove that `(ab + cd + ef)^2 = (a^2 + c^2 + e^2) (b^2 + d^2 + f^2)`.
The ratio of boys and girls in a school is 12 : 5. If the number of girls is 840, the total strength of the school is
If b is the mean proportional between a and c, prove that a, c, a² + b², and b² + c² are proportional.
If a, b, c and d are in proportion, prove that: `abcd [(1/a^2 + 1/b^2 + 1/c^2 + 1/d^2]` = a2 + b2 + c2 + d2
Find the missing number in the box in the proportions:
`8/square = 3.2/4`
Bachhu Manjhi earns Rs. 24000 in 8 months. At this rate, in how many months does he earn Rs. 42000?
Determine if the following are in proportion.
4, 6, 8, 12
If x : y = y : z, then x2 : y2 is ______.