Advertisements
Advertisements
Question
If three quantities are in continued proportion, show that the ratio of the first to the third is the duplicate ratio of the first to the second.
Solution
Let x, y and z are the three quantities which are in continued proportion
Then, x : y :: y : z => y2 = xz
Now, we have to prove that
x : z = x2 : y2
⇒ xy2 = x2z
LHS
= xy2 = x(xz) = x2z = RHS
LHS = RHS
APPEARS IN
RELATED QUESTIONS
If a, b, c are in continued proportion and a(b - c) = 2b, prove that `a - c = (2(a + b))/a`
If `(28 - x)` is the mean proportional of `(23 - x)`and `(19 - x)` then find the value of x.
Find the value of the unknown in the following proportion :
3 : 4 : : p : 12
If y is the mean proportional between x and z, show that :
xyz (x+y+z)3 =(xy+yz+xz)3
If a, b, c are in continued proportion and a(b – c) = 2b, prove that: `a - c = (2(a + b))/a`.
The weight of 65 books is 13 kg.
(i) What is the weight of 80 such books?
(ii) How many such books weigh 6.4 kg?
If a, b, c are in continued proportion, prove that: `(1)/a^3 + (1)/b^3 + (1)/c^3 = a/(b^2c^2) + b/(c^2a^2) + c/(a^2b^2)`
If a, b, c are in continued proportion, prove that: a : c = (a2 + b2) : (b2 + c2)
Determine if the following are in proportion.
4, 6, 8, 12
If x : y = y : z, then x2 : y2 is ______.