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If `X =2/3` and X = -3 Are the Roots of the Quadratic Equation `Ax^2+2ax+5x ` Then Find The Value of a and B. - Mathematics

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प्रश्न

If `x =2/3` and x = -3 are the roots of the quadratic equation `ax^2+2ax+5x ` then find the value of a and b.

उत्तर

Given:  `ax2 + 7x + b = 0` 

Since, `x=2/3`is the root of the above quadratic equation
Hence, it will satisfy the above equation. 
Therefore, we will get , 

`a(2/3)^2+7(2/3)+b=0` 

⇒ `4/9a+14/3+b=0` 

⇒ `4a+42+9b=0` 

⇒ `4a+9b=-42`                          .............(1) 

Since, x = –3 is the root of the above quadratic equation
Hence, It will satisfy the above equation.
Therefore, we will get 

`a(-3)^2+7(-3)+b=0` 

`⇒ 9a-21+b=0` 

`⇒9a+b=21`                        ......................(2) 

From (1) and (2), we get
a = 3, b = –6

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पाठ 2: Polynomials - Exercises 1

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