Advertisements
Advertisements
प्रश्न
If x = 2, y = 5 and z = 4, find the value of the following:
`("x"^2"y"^2"z"^2)/"xz"`
उत्तर
`("x"^2"y"^2"z"^2)/"xz"`
= `((2)^2xx(5)^2xx(4)^2)/(2xx4)`
= (2)2−1 × (5)2 × (4)2−1
= 2 × 5 × 5 × 4
= 200
APPEARS IN
संबंधित प्रश्न
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
a − b + y = ................
If a = 3, b = 0, c = 2 and d = 1, find the value of a2 + b2 − c2 + d2
If m = 2, find the difference between the values of 4m3 and 3m4.
Simplify:
`"a"−[−{−(a−overline("b"-"c"))}]`
Fill in the blank:
3x − z + y = 3x − (..............)
Fill in the blank:
5a + 4b + 4x − 2c = 4x − (...........)
If x = 2, y = 3 and z = 4, find the value of 3x2 – 4y2 + 2z2.
If x = 3, y = 2 and z = 1; find the value of xy
If x = 3, y = 2 and z = 1; find the value of yx
Multiply and then evaluate:
(x – 2y + z) and (x – 3z); when x = − 2, y = − 1 and z = 1.
