Advertisements
Advertisements
प्रश्न
If x + 5 is the mean proportional between x + 2 and x + 9; find the value of x.
उत्तर
Given, x + 5 is the mean proportional between x + 2 and x + 9.
`\implies` (x + 2), (x + 5) and (x + 9) are in continued proportion.
`\implies` (x + 2) : (x + 5) = (x + 5) : (x + 9)
`\implies` (x + 5)2 = (x + 2)(x + 9)
`\implies` x2 + 25 + 10x = x2 + 2x + 9x + 18
`\implies` 25 – 18 = 11x – 10x
`\implies` x = 7
APPEARS IN
संबंधित प्रश्न
Find the fourth proportional to 1.5, 4.5 and 3.5
If y is the mean proportional between x and z; show that xy + yz is the mean proportional between x2 + y2 and y2 + z2.
If `x/a = y/b = z/c` prove that `(2x^3 - 3y^3 + 4z^3)/(2a^3 - 3b^3 + 4c^3) = ((2x - 3y + 4z)/(2a - 3b + 4c))^3`
Using properties of proportion, solve for x:
`(sqrt(x + 5) + sqrt(x - 16))/(sqrt(x + 5) - sqrt(x - 16)) = 7/3`
What least number must be added to each of the numbers 5, 11, 19 and 37, so that they are in proportion?
Find the value of x in each of the following proportions:
x : 92 : : 87 : 116
Write (T) for true and (F) for false in case of the following:
51 : 68 : : 85 : 102
3 : 5 : : `square` : 20
Find the missing number in the box in the proportions:
`square/18 = 2/9`
Write True (T) or False (F) against the following statement:
5.2 : 3.9 : : 3 : 4
