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In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35 cm length of the wire. If the cell is replaced by another cell and the balance point shifts to 63 cm, - Physics

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प्रश्न

In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35 cm length of the wire. If the cell is replaced by another cell and the balance point shifts to 63 cm, what is the emf of the second cell?

संख्यात्मक

उत्तर

Emf of the cell1, ξ1 = 1.25 V

Balancing length of the cell, l1 = 35 cm = 35 x 10-2 m

Balancing length after interchanged, l2 = 63 cm = 63 x 10-2 m

Emf of the cell1, ξ2 = ?

The ration of emf’s, `ξ_1/ξ_2 = l_1/l_2`

The ration of emf’s, ξ2 = ξ1 = `(l_2/l_1)`

= 1. 25 `xx ((63 xx 10^-2)/(35 xx 10^-2)) = 12.5 xx 1.8` 

ξ2 = 2.25 V.

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पाठ 2: Current Electricity - Evaluation [पृष्ठ १२३]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 2 Current Electricity
Evaluation | Q IV. 14. | पृष्ठ १२३

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