Advertisements
Advertisements
प्रश्न
In a two-digit number, the ten’s digit is bigger. The product of the digits is 27 and the difference between two digits is 6. Find the number.
उत्तर
Given, the difference between the two digits is 6 and the ten’s digit is bigger than the unit’s digit.
So, let the unit’s digit be x and ten’s digit be (x + 6).
From the given condition, we have:
x(x + 6) = 27
x2 + 6x – 27 = 0
x2 + 9x – 3x – 27 = 0
x(x + 9) – 3(x + 9) = 0
(x + 9)(x – 3) = 0
x = –9, 3
Since, the digits of a number cannot be negative.
So, x = 3.
Unit’s digit = 3
Ten’s digit = 9
Thus, the number is 93.
APPEARS IN
संबंधित प्रश्न
A positive number is divided into two parts such that the sum of the squares of the two parts is 20. The square of the larger part is 8 times the smaller part. Taking x as the smaller part of the two parts, find the number.
The product of two consecutive integers is 56. Find the integers.
The sum of a number and its reciprocal is 4.25. Find the number.
Two natural numbers differ by 3. Find the numbers, if the sum of their reciprocals is `7/10`.
Three positive numbers are in the ratio `1/2 : 1/3 : 1/4`. Find the numbers if the sum of their squares is 244.
Three consecutive natural numbers are such that the square of the middle number exceeds the difference of the squares of the other two by 60. Assume the middle number to be x and form a quadratic equation satisfying the above statement. Hence; find the three numbers.
The sum S of first n even natural numbers is given by the relation S = n(n + 1). Find n, if the sum is 420.
Given that the sum of the squares of the first seven natural numbers is 140, then their mean is ______.
The product of two whole numbers, each greater than 4, is 35; the numbers are ______.
The sum of two whole numbers is 18 and their product is 45, the numbers are ______.
