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प्रश्न
In a ΔABC, AD is the bisector of ∠A, meeting side BC at D.
If BD = 2.5cm, AB = 5cm and AC = 4.2cm, find DC.
उत्तर
We have,
∠BAD = ∠CAD
We know that, the internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.
`therefore"BD"/"DC"="AB"/"AC"`
`rArr2.5/"DC"=5/4.2`
`rArr"DC"=(2.5xx4.2)/5`
`=(25xx42)/(5xx100)=(5xx42)/100=210/100=2.1 `cm
∴ DC = 2.1 cm
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