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प्रश्न
In a ΔABC, AD is the bisector of ∠A, meeting side BC at D.
If BD = 2cm, AB = 5cm and DC = 3cm, find AC.
उत्तर
We have,
AD is the bisector of ∠A
We know that, the internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.
`therefore"BD"/"DC"="AB"/"AC"`
`rArr2/3=5/"AC"`
`rArr"AC"=(5xx3)/2=15/2`
⇒ AC = 7.5 cm
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