Advertisements
Advertisements
प्रश्न
In the following reaction between lead sulphide and hydrogen peroxide:
PbS (s) + 4H2O2(aq) → PbSO4(s) + 4H2O(1)
(a) which substance is reduced?
(b) Which substance is oxidised?
उत्तर
(a) Hydrogen peroxide (H2O2) is reduced.
(b) Lead sulphide (PbS) is oxidised.
This is because lead sulphide gains oxygen, while hydrogen peroxide loses oxygen.
APPEARS IN
संबंधित प्रश्न
What are anti-oxidants? Why are they added to fat and oil containing foods?
Fill in the following blanks with suitable words:
The addition of hydrogen to a substance is called ........ whereas removal of hydrogen is called .......
In the reaction represented by the equation:
MnO2 + 4HCl → MnCl2 + 2H2O + Cl2
(i) name the substance oxidised.
(ii) name the oxidising agent.
(iii) name the substance reduced.
(iv) name the reducing agent.
In the following reaction: A+ + B → A + B+. Write half-reactions for this reaction and name:
- oxidizing agent
- substance oxidized
- reducing agent
Name:
a solid that is an oxidizing agent.
Complete and balance the following equation:
\[\ce{K + H2O -> }\]________+ ________
Define Oxidation reaction.
The tarnishing of metals is an example of ______ reaction.
What are reducing agents? Give examples.
Answer the questions based on the equation below:
\[\ce{CH3 - CH2 - OH ->[{[O]}][K2Cr2O7/H2SO4] CH3 - COOH}\]
- What type of reaction is it?
- What is the role of the chemical written on the arrow?
- Give one example of one such type of chemical as in answer (b).
