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In the Following Reaction Between Lead Sulphide and Hydrogen Peroxide: Pbs (S) + 4h2o2(Aq) → Pbso4(S) + 4h2o(1) (A) Which Substance is Reduced? (B) Which Substance is Oxidised? - Science

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Question

In the following reaction between lead sulphide and hydrogen peroxide:

PbS (s) + 4H2O2(aq) → PbSO4(s) + 4H2O(1)

(a) which substance is reduced?
(b) Which substance is oxidised?

 

Solution

(a) Hydrogen peroxide (H2O2) is reduced.

(b) Lead sulphide (PbS) is oxidised.
This is because lead sulphide gains oxygen, while hydrogen peroxide loses oxygen.

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Chapter 1: Chemical Reactions and Equations - Exercise 2 [Page 46]

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Lakhmir Singh Chemistry (Science) [English] Class 10
Chapter 1 Chemical Reactions and Equations
Exercise 2 | Q 21 | Page 46
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