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प्रश्न
In ∆PQR, the measures of ∠P and ∠Q are equal and m∠PRQ = 70°. Find the measures of the following angles.
- m∠PRT
- m∠P
- m∠Q
उत्तर
(i) ∠PRQ + ∠PRT = 180∘ ...(Linear pair angles)
⇒ 70° + ∠PRT = 180°
⇒ ∠PRT = 180∘ − 70°
= 110∘
Hence, the measure of ∠PRT is 110∘.
(ii) Now, ∠PRT is the exterior angle of ∆PQR.
∴ m∠P + m∠Q = m∠PRT ...(Exterior angle property)
∴ m∠P + m∠P = 110 ...(∠P = ∠Q)
∴ 2m∠P = 110
∴ m∠P = `110/2`
∴ m∠P = 55°
(iii) In ΔPQR
∴ m∠P + m∠Q = m∠PRT ...(Exterior angle property)
∴ m∠Q + m∠Q = 110 ...(∠P = ∠Q)
∴ 2m∠Q = 110
∴ m∠Q = `110/2`
∴ m∠Q = 55°
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