Advertisements
Advertisements
प्रश्न
Is it possible to have a polygon whose sum of interior angles is 780°?
उत्तर
Let the number of sides in the polygon be n.
∴ (n - 2) x 180° = 780°
⇒ 180°n - 360° = 780°
⇒ 180°n = 1140°
⇒ n = `(1140°)/(180°)`
= `6(1)/(3)`
Since the number of sides of a polygon cannot be in a fraction, therefore the polygon is not possible.
APPEARS IN
संबंधित प्रश्न
The ratio between an exterior angle and an interior angle of a regular polygon is 2 : 3. Find the number of sides in the polygon.
Two angles of an eight-sided polygon are 142o and 176o. If the remaining angles are equal to each other; find the magnitude of each of the equal angles.
In a pentagon ABCDE, AB is parallel to DC and ∠A: ∠E : ∠D = 3: 4: 5. Find angle E.
Find the measure of each interior angle of a regular polygon of: 6 sides
Find the number of sides in a regular polygon, when each exterior angle is: 72°
A heptagon has three angles equal to 120°, and the other four angles are equal. Find all the angles.
KL, LM and MN are three consecutive sides of a regular polygon. If ∠LKM = 20°, find the interior angle of the polygon and the number of sides of the polygon.
Find the value of each angle of a heptagon If three of its angles measure 132° each and the remaining four.
The number angle of a regular polygon is double the exterior angle. Find the number of sides of the polygon.
Each exterior angle of a regular polygon is `(1)/"P" `times of its interior angle. Find the number of sides in the polygon.