Advertisements
Advertisements
प्रश्न
Each exterior angle of a regular polygon is `(1)/"P" `times of its interior angle. Find the number of sides in the polygon.
उत्तर
Each interior angle of a regular polygon of n sides = `(("n" - 2) xx 180°)/"n"`
Each interior angle of a regular polygon of n sides = `(360°)/"n"`
Now,
`(360°)/"n" = (1)/"p" xx (("n" - 2) xx 180°)/"n"`
360° = `(1)/"p" xx ("n" - 2) xx 180°`
⇒ n = 2 = `"p" xx (360°)/(180°)`
⇒ n - 2 = 2p
⇒ n = 2p + 2
⇒ n = 2(p + 1)
Thus, the number of sides of a goven regular polygon is 2(p + 1).
APPEARS IN
संबंधित प्रश्न
The sum of the interior angles of a polygon is four times the sum of its exterior angles.
Find the number of sides in the polygon.
AB, BC, and CD are the three consecutive sides of a regular polygon. If BAC = 15°;
Find:
- Each interior angle of the polygon.
- Each exterior angle of the polygon.
- The number of sides of the polygon.
Two angles of an eight-sided polygon are 142o and 176o. If the remaining angles are equal to each other; find the magnitude of each of the equal angles.
Find the number of sides in a regular polygon, when each interior angle is: 120°
Find the number of sides in a regular polygon, when each exterior angle is: 60°
Calculate the measure of each angle of a regular polygon of 20 sides.
Is it possible to have a polygon whose sum of interior angles is 7 right angles?
In a polygon, there are 3 right angles and the remaining angles are equal to 165°. Find the number of sides in the polygon.
If the difference between an exterior angle of a regular polygon of 'n' sides and an exterior angle of another regular polygon of '(n + 1)' sides is equal to 4°; find the value of 'n'.
The difference between an exterior angle of (n - 1) sided regular polygon and an exterior angle of (n + 2) sided regular polygon is 6°. Find the value of n.