Advertisements
Advertisements
प्रश्न
Find the number of sides in a regular polygon, when each interior angle is: 120°
उत्तर
Each interior angle of a regular polygon
= `(("n" - 2) xx 180°)/"n"`
⇒ `(("n" - 2) xx 180°)/"n"` = 120°
⇒ 180°(n - 2) = 120°(n)
⇒ 3(n - 2) = 2n
⇒ n = 6.
APPEARS IN
संबंधित प्रश्न
In a parallelogram ABCD, AB = 20 cm and AD = 12 cm. The bisector of angle A meets DC at E and BC produced at F.
Find the length of CF.
Find the sum of the interior angles of a polygon of: 7 sides
Find the measure of each interior angle of a regular polygon of: 15 sides
Find each exterior angle of a regular polygon of: 9 sides
Is it possible to have a polygon whose sum of interior angles is 780°?
Is it possible to have a polygon whose each interior angle is 124°?
If the difference between an exterior angle of a regular polygon of 'n' sides and an exterior angle of another regular polygon of '(n + 1)' sides is equal to 4°; find the value of 'n'.
The number of sides of two regular polygons are in the ratio 2 : 3 and their interior angles are in the ratio 9 : 10. Find the number of sides of each polygon.
The exterior angle of a regular polygon is one-third of its interior angle. Find the number of sides of the polygon.
The difference between an exterior angle of (n - 1) sided regular polygon and an exterior angle of (n + 2) sided regular polygon is 6°. Find the value of n.