Advertisements
Advertisements
प्रश्न
Let A = {1, 2, 3, 7} and B = {3, 0, –1, 7}, the following is relation from A to B?
R4 = {(7, –1), (0, 3), (3, 3), (0, 7)}
उत्तर
A = {1, 2, 3, 7} B = {3, 0, –1, 7}
A × B = {1, 2, 3} × {3, 0, –1, 7}
A × B = {(1, 3) (1, 0) (1, –1) (1, 7) (2, 3) (2, 0) (2, –1) (2, 7) (3, 3) (3, 0) (3, –1) (3, 7) (7, 3) (7, 0) (7, –1) (7, 7)}
R4 = {(7, –1), (0, 3), (3, 3), (0, 7)}
It is not a relation, there is no element of (0, 3) and (0, 7) in A × B
APPEARS IN
संबंधित प्रश्न
Find the inverse relation R−1 in each of the cases:
(iii) R is a relation from {11, 12, 13} to (8, 10, 12] defined by y = x − 3.
If R is a relation from set A = (11, 12, 13) to set B = (8, 10, 12) defined by y = x − 3, then write R−1.
Let R be a relation from a set A to a set B, then
Write the relation in the Roster Form. State its domain and range
R7 = {(a, b)/a, b ∈ N, a + b = 6}
Answer the following:
Show that the following is an equivalence relation
R in A is set of all books. given by R = {(x, y)/x and y have same number of pages}
Let X = {a, b, c, d} and R = {(a, a), (b, b), (a, c)}. Write down the minimum number of ordered pairs to be included to R to make it reflexive
Choose the correct alternative:
The number of relations on a set containing 3 elements is
If R1 = {(x, y) | y = 2x + 7, where x ∈ R and – 5 ≤ x ≤ 5} is a relation. Then find the domain and Range of R1.
Is the given relation a function? Give reasons for your answer.
f = {(x, x) | x is a real number}
A relation on the set A = {x : |x| < 3, x ∈ Z}, where Z is the set of integers is defined by R = {(x, y) : y = |x| ≠ –1}. Then the number of elements in the power set of R is ______.