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प्रश्न
Lines mx + 3y + 7 = 0 and 5x – ny – 3 = 0 are perpendicular to each other. Find the relation connecting m and n.
उत्तर
mx + 3y + 7 = 0
3y = – mx − 7
`y = (-mx)/3 - 7/3`
Slope of this line = `(-m)/3`
5x − ny − 3 = 0
ny = 5x − 3
`y = (5x)/n - 3/n`
Slope of this line = `5/n`
Since, the lines are perpendicular; the product of their slopes is −1.
∴ `((-m)/3)(5/n) = -1`
5m = 3n
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