Advertisements
Advertisements
प्रश्न
Multiply the monomial by the binomial and find the value for x = −1, y = 0.25 and z = 0.05: −3x(y2 + z2)
उत्तर
To find the product, we will use distributive law as follows:
\[- 3x\left( y^2 + z^2 \right)\]
\[ = - 3x \times y^2 + \left( - 3x \right) \times z^2 \]
\[ = - 3x y^2 - 3x z^2\]
Substituting x = \[-\] 1, y = 0.25 and z = 0.05 in the result, we get:
\[- 3x y^2 - 3x z^2 \]
\[ = - 3\left( - 1 \right) \left( 0 . 25 \right)^2 - 3\left( - 1 \right) \left( 0 . 05 \right)^2 \]
\[ = - 3\left( - 1 \right)\left( 0 . 0625 \right) - 3\left( - 1 \right)\left( 0 . 0025 \right)\]
\[ = 01875 + 0 . 0075\]
\[ = 0 . 195\]
APPEARS IN
संबंधित प्रश्न
Multiply the binomials.
(2x + 5) and (4x − 3)
Multiply the binomials.
`(3/4 a^2 + 3b^2) and 4(a^2 - 2/3 b^2)`
Find the product.
(x + 7y) (7x − y)
Find the product.
(a2 + b) (a + b2)
Multiply the monomial by the binomial and find the value for x = −1, y = 0.25 and z = 0.05: 15y2(2 − 3x)
Find the product of the following binomial: (2x + y)(2x + y)
Find the product of the following binomial: \[\left( \frac{4x}{5} - \frac{3y}{4} \right)\left( \frac{4x}{5} + \frac{3y}{4} \right)\]
Find the product of the following binomial: (2a3 + b3)(2a3 − b3)
Using the formula for squaring a binomial, evaluate the following: (1001)2
Using the formula for squaring a binomial, evaluate the following: (999)2