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प्रश्न
PQ is perpendicular to BA and BD is perpendicular to AP.PQ and BD intersect at R. Prove that ΔABD ∼ ΔAPQ and `"AB"/"AP" = "BD"/"PQ"`.
उत्तर
In ΔABD and ΔAPQ,
∠BDA ∠PQA = 90°
∠A = ∠A
Therefore, ΔABD ∼ ΔAPQ ...(AA axiom)
And hence, `"AB"/"AP" = "BD"/"PQ"`.
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