Advertisements
Advertisements
प्रश्न
Rs. 480 is divided equally among ‘x’ children. If the number of children were 20 more then each would have got Rs. 12 less. Find ‘x’.
उत्तर १
Share of each child = ₹`(480)/x`
Now, number of children
= x + 20
∵ Share of each child
= ₹`(480)/(x + 20)`
Now, According to the question
`(480)/x - (480)/(x + 20)` = 12
⇒ `(480 x + 9,600 - 480x)/(x(x + 20)` = 12
⇒ 9,600 = 12x (x + 20)
⇒ 800 = x2 + 20x
⇒ x2 + 20x - 800 = 0
⇒ x2 + 40x - 20x - 800 = 0
⇒ x(x + 40) - 20 (x + 40) = 0
⇒ (x - 20) (x + 40) = 0
⇒ x = 20
or
⇒ x = -40 ...(not possible)
∴ x = 20
उत्तर २
Share of each child = ₹`(480)/x`
According to the question
`(480)/(x + 20) = (480)/x - 12`
⇒ `(480)/(x + 20) = (480 - 12x)/x`
⇒ `(480)/(x + 20) = (12(40 - x))/x`
⇒ (x + 20)(40 - x) = 40x
⇒ 40x x2 + 800 - 20x = 40x
⇒ x2 + 20x - 800 = 0
⇒ x2 + 40x - 20x - 800 = 0
⇒ x(x + 40) -20(x + 40) = 0
⇒ (x + 40)(x - 20) = 0
⇒ x = -40, x = 20
-ve value of x is not possible
∴ No. of children = 20.
संबंधित प्रश्न
The difference of two numbers is 4. If the difference of their reciprocals is 4/21. Find the numbers.
If the equation x2 + 4x + k = 0 has real and distinct roots, then
Solve equation using factorisation method:
`x = (3x + 1)/(4x)`
By increasing the speed of a car by 10 km/hr, the time of journey for a distance of 72 km. is reduced by 36 minutes. Find the original speed of the car.
Solve the following quadratic equation by factorisation method:
`x/(x + 1) + (x + 1)/x = (34)/(15') x ≠ 0, x ≠ -1`
Solve the equation x4 + 2x3 - 13x2 + 2x + 1 = 0.
In each of the following determine whether the given values are solutions of the equation or not.
9x2 - 3x - 2 = 0; x = `-(1)/(3), x = (2)/(3)`
Find the values of x if p + 7 = 0, q – 12 = 0 and x2 + px + q = 0,
Solve the following equation by factorisation :
x2 + 6x – 16 = 0
Solve the following quadratic equation by factorisation method:
x2 + x – 20 = 0