मराठी

Show that the magnetic field B at a point in between the plates of a parallel-plate capacitor during charging is εε0μr2dEdt (symbols having usual meaning). - Physics

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प्रश्न

Show that the magnetic field B at a point in between the plates of a parallel-plate capacitor during charging is `(ε_0mu_r)/2 (dE)/(dt)` (symbols having usual meaning).

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उत्तर

Let us assume Id be the displacement current in the region between two plates of parallel plate capacitor, in the figure.


The magnetic field at a point between two plates of capacitor  at a perpendicular distance r from the axis of plates is given by

B = `(mu_0 2I_d)/(4pir) = mu_0/(2pir) I_d = mu_0/(2pir) xx ε_r (dphi_E)/(dt)`  ......`[because I_d = (E_0dphi_E)/(dt)]`

⇒ B = `(mu_0ε_r)/(2pir) d/(dt) (Epir^2) = (mu_0ε_r)/(2pir) pir^2 (dF)/(dt)`

⇒ B = `(mu_0ε_r)/2 (dE)/(dt)`  .....`[because phi_E = Epir^2]`

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पाठ 8: Electromagnetic Waves - MCQ I [पृष्ठ ५१]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 12
पाठ 8 Electromagnetic Waves
MCQ I | Q 8.21 | पृष्ठ ५१

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संबंधित प्रश्‍न

A parallel plate capacitor (Figure) made of circular plates each of radius R = 6.0 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V ac supply with a (angular) frequency of 300 rad s−1.

  1. What is the rms value of the conduction current?
  2. Is the conduction current equal to the displacement current?
  3. Determine the amplitude of B at a point 3.0 cm from the axis between the plates.


When an ideal capacitor is charged by a dc battery, no current flows. However, when an ac source is used, the current flows continuously. How does one explain this, based on the concept of displacement current?


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Without the concept of displacement current it is not possible to correctly apply Ampere’s law on a path parallel to the plates of parallel plate capacitor having capacitance C in ______.


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  1. The associated magnetic field is given as `B = 1/c hatk xx E = 1/ω (hatk xx E)`.
  2. The electromagnetic field can be written in terms of the associated magnetic field as `E = c(B xx hatk)`.
  3. `hatk.E = 0, hatk.B` = 0.
  4. `hatk xx E = 0, hatk xx B` = 0.

Sea water at frequency ν = 4 × 108 Hz has permittivity ε ≈ 80 εo, permeability µ ≈ µo and resistivity ρ = 0.25 Ω–m. Imagine a parallel plate capacitor immersed in seawater and driven by an alternating voltage source V(t) = Vo sin (2πνt). What fraction of the conduction current density is the displacement current density?


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[take ε0 = 8.85 × 10-12 F/m]


Draw a neat labelled diagram of displacement current in the space between the plates of the capacitor.


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