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प्रश्न
Show the distribution of electrons in oxygen atom (atomic number 8) using orbital diagram.
उत्तर
The electronic configuration of oxygen atom is 1s2 2s2 2p4 and its orbital diagram is given by
0 =
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संबंधित प्रश्न
Which atom is indicated by the following configuration?
[Ne] 3s2 3p3
Which atom is indicated by the following configuration?
[Ar] 4s2 3d1.
An atomic orbital has n = 3. What are the possible values of l and ml?
Which of the following orbitals are possible?
1p, 2s, 2p and 3f
Indicate the number of unpaired electrons in Cr.
Indicate the number of unpaired electrons in Fe.
Indicate the number of unpaired electrons in Kr.
Which of the following statements is correct?
(a) The electronic configuration of Cr is (Ar) 3d5 4s1.
(b) The magnetic quantum number may have a negative value.
(c) In the ground state of an atom, the orbitals are filled in order of their increasing energies.
(d) The total number of nodes are given by n − 2.
Choose the most appropriate answer from the options given below:
The number of 4f electron in the ground state electronic configuration Gd2+ is ______. (Atomic number of Gd = 64)
The correct set of four quantum numbers for the valence electrons of the rubidium atom (Z = 37) is ______.