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प्रश्न
Nickel atom can lose two electrons to form \[\ce{Ni^{2+}}\] ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons.
उत्तर
\[\ce{Ni}\] (28): 1s2 2s2 2p6 3s2 3p6 3d8 4s2
\[\ce{Ni^{2+}}\] (26): 1s2 2s2 2p6 3s2 3p6 3d8
Hence, to form \[\ce{Ni^{2+}}\] ion, it will lose 2 electrons from 4s orbital.
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संबंधित प्रश्न
Using s, p, d notations, describe the orbital with the following quantum numbers n = 3; l =1.
State the order of filling atomic orbitals following Aufbau principle.
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n = 4, l = 2
Write condensed orbital notation of electronic configuration of the following element:
Oxygen (Z = 8)
Draw shapes of 2p orbitals.
Which one of the following is NOT possible?
The number of radial nodes for 3p orbital is ______.
Which of the following sets of quantum numbers are correct?
| `n` | `l` | `m_l` | |
| (i) | 1 | 1 | +2 |
| (ii) | 2 | 1 | +1 |
| (iii) | 3 | 2 | –2 |
| (iv) | 3 | 4 | –2 |
Which of the following orbitals are degenerate?
3dxy, 4dxy 3dz2, 3dyz, 4dyz, 4dz2
Calculate the total number of angular nodes and radial nodes present in 3p orbital.
