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सी.आई.एस.सी.ई.आयसीएसई ICSE Class 7

Simplify, Giving Solution with Positive Index (2a3)4 (4a2)2 - Mathematics

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प्रश्न

Simplify, giving Solution with positive index

(2a3)4 (4a2)2 

बेरीज

उत्तर

(2a3)4 (4a2)2 

= (2a3)4 (22a2)2 

= 24 a3×4 . 22×2 a2×2 

= 24a12 . 24a4 

= 24+4 a12+4 

= 28a16 

= 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × a16 

= 256 a16 

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Laws of Exponents (Through Observing Patterns to Arrive at Generalisation.)
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Exponents (Including Laws of Exponents) - Exercise 5 (B)

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सेलिना Concise Mathematics [English] Class 7 ICSE
पाठ 5 Exponents (Including Laws of Exponents)
Exercise 5 (B) | Q 3.17
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