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प्रश्न
Solve :
`3/x - 2/y = 0 and 2/x + 5/y = 19` Hence, find 'a' if y = ax + 3.
उत्तर
`3/x - 2/y = 0` ......(1)
`2/x + 5/y = 19` .......(2)
Multiplying equation no. (1) by 5 and (2) by 2.
`15/x - 10/y = 0` ........(3)
`4/x + 10/y = 38` ........(4)
Adding (3) and (4),
`15/x - 10/y = 0`
+ `4/x + 10/y = 38`
`19/x = 38`
x = `1/2`
From (1)
`3(1/2) - 2/y = 0`
y = `1/3`
∴ y = ax + 3
`1/3 = a(1/2) + 3`
`a/2 = -8/3`
`a = -16/3`
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