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प्रश्न
Solve :
5x + `8/y` = 19
3x - `4/y` = 7
उत्तर
5x + `8/y` = 19 ....(1)
3x - `4/y` = 7 .....(2)
Multiplying equation (2) by 2, We get,
6x - `8/y` = 14 ......(3)
Adding (1) and (3), We get,
5x + `8/y` = 19
+ 6x - `8/y` = 14
11x = 33
x = 3
Substituting x = 3 in equation (1), We get
5(3) + `8/y` = 19
15 + `8/y` = 19
`8/y` = 19 - 15
y = `8/4`
y = 2
APPEARS IN
संबंधित प्रश्न
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`9/x - 4/y = 8`
`13/x + 7/y = 101`
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`3/x + 2/y = 10`
`9/x - 7/y = 10.5`
Solve :
4x + `6/y` = 15 and 3x - `4/y` = 7. Hence, find a if y = ax - 2.
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`3/x - 2/y = 0 and 2/x + 5/y = 19` Hence, find 'a' if y = ax + 3.
Solve :
`20/[ x + y ] + 3/[ x - y ] = 7`
`8/[ x - y ] - 15/[ x + y ] = 5`
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`25/[ 3x - 2y ] - 8.50/[ 3x + 4y ] = 4.5`
Solve:
x + y = 2xy
x - y = 6xy
Solve :
x+ y = 7xy
2x - 3y = - xy
Solve :
`[2xy]/[ x + y ] = 3/2`
`[xy]/[ 2x - y ] = -3/10`
x + y ≠ 0 and 2x - y ≠ 0
Solve :
`3/(2x) + 2/(3y) = -1/3`
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