Advertisements
Advertisements
प्रश्न
Solve the following equation: 2x2 - x - 6 = 0
उत्तर
2x2 - x - 6 = 0
`"x"^2 - 1/2 "x" - 3 = 0`
`"x"^2 - 2"x" + 3/2"x" - 3 = 0 `
`"x"("x" - 2) + 3/2 ("x" - 2) = 0`
`("x" - 2)("x" + 3/2) = 0`
(x - 2) = 0 , `("x" + 3/2) = 0`
x = 2 , x = `-3/2`
APPEARS IN
संबंधित प्रश्न
The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.
Solve the following quadratic equations by factorization:
(x − 4) (x + 2) = 0
Divide 29 into two parts so that the sum of the squares of the parts is 425.
Sum of two numbers is 16. The sum of their reciprocals is 1/3. Find the numbers.
If \[\left( a^2 + b^2 \right) x^2 + 2\left( ab + bd \right)x + c^2 + d^2 = 0\] has no real roots, then
Solve equation using factorisation method:
`5/("x" -2) - 3/("x" + 6) = 4/"x"`
Solve the following equation by factorization
2x2 – 9x + 10 = 0,when x∈N
Solve the following equation by factorization
`sqrt(x(x - 7)) = 3sqrt(2)`
Find two consecutive odd integers such that the sum of their squares is 394.
Two squares have sides A cm and (x + 4) cm. The sum of their areas is 656 sq. cm.Express this as an algebraic equation and solve it to find the sides of the squares.
