Advertisements
Advertisements
प्रश्न
Solve equation using factorisation method:
`5/("x" -2) - 3/("x" + 6) = 4/"x"`
उत्तर
`5/("x" -2) - 3/("x" + 6) = 4/"x"`
⇒ `(5("x" + 6) -3("x" -2))/(("x" -2)("x" + 6)) = 4/"x"`
⇒ `(5"x" + 30 - 3"x" + 6)/("x"^2 + 6"x" - 2"x" - 12) = 4/"x"`
⇒ `(2"x" + 36)/("x"^2 + 4"x" - 12) = 4/"x"`
⇒ 4x2 + 16x - 48 = 2x2 + 36x
⇒ 2x2 - 20x - 48 = 0
⇒ x2 - 10x - 24 = 0
⇒ x2 - 12x + 2x - 24 = 0
⇒ x(x - 12) + 2(x - 12) = 0
⇒ (x - 12) (x + 2) = 0
If x - 12 = 0 or x + 2 = 0
then x = 12 or x = -2
APPEARS IN
संबंधित प्रश्न
Solve for x
`(2x)/(x-3)+1/(2x+3)+(3x+9)/((x-3)(2x+3)) = 0, x!=3,`
Solve the following quadratic equations by factorization: \[\frac{1}{2a + b + 2x} = \frac{1}{2a} + \frac{1}{b} + \frac{1}{2x}\]
If a and b can take values 1, 2, 3, 4. Then the number of the equations of the form ax2 +bx + 1 = 0 having real roots is
The value of c for which the equation ax2 + 2bx + c = 0 has equal roots is
If y = 1 is a common root of the equations \[a y^2 + ay + 3 = 0 \text { and } y^2 + y + b = 0\], then ab equals
Solve the following equation: `10"x" - 1/"x" = 3`
The perimeter of the right angled triangle is 60cm. Its hypotenuse is 25cm. Find the area of the triangle.
Solve equation using factorisation method:
x2 – 10x – 24 = 0
In a P.T. display, 480 students are arranged in rows and columns. If there are 4 more students in each row than the number of rows, find the number of students in each row.
A shopkeeper buys a certain number of books for Rs 960. If the cost per book was Rs 8 less, the number of books that could be bought for Rs 960 would be 4 more. Taking the original cost of each book to be Rs x, write an equation in x and solve it to find the original cost of each book.