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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Solve the following. A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5g neon. If the pressure of the mixture of the gases in the cylinder is 25 bar. What is the partial pressure - Chemistry

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प्रश्न

Solve the following.

A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5g neon. If the pressure of the mixture of the gases in the cylinder is 25 bar. What is the partial pressure of dioxygen and neon in the mixture?

संख्यात्मक

उत्तर

Given:
mO2 = 70.6 g,
mNe = 167.5 g,
PTotal = 25 bar

To find: Partial pressure of each gas

Formula: P1 = x1 × PTotal

Calculation:

Determine number of moles (n) of each gas using formula:
n = `"m"/"M"`

nO2 = `(70.6 "g")/(32 "g mol"^-1)` = 2.206 mol

nNe = `(167.5 "g")/(20 "g mol"^-1)` = 8.375 mol

Determine the mole fraction of each gas using the formula:

x = `"n"/("n"_"Total")`

`""^"x""O"_2=(""^"n""O"_2)/(""^"n""O"_2+"n"_"Ne")=(2.206  "mol")/((2.206+8.375)  "mol")=(2.206  "mol")/(10.581  "mol")=0.208`

xNe = `("n"_"Ne")/("n"_"Total")=(8.375  "mol")/(10.581  "mol")` = 0.792

Calculate the partial pressure of each gas:

PO2 = xO2 × PTotal = 0.208 × 25 bar = 5.2 bar

PNe = xNe × PTotal = 0.792 × 25 bar = 19.8 bar

The partial pressure of dioxygen and neon are 5.2 bar and 19.8 bar respectively.

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Ideal Gas Equation
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पाठ 10: States of Matter - Exercises [पृष्ठ १५९]

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बालभारती Chemistry [English] 11 Standard
पाठ 10 States of Matter
Exercises | Q 5. (I) | पृष्ठ १५९

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