Advertisements
Advertisements
प्रश्न
Solve the following equation by using formula :
256x2 – 32x + 1 = 0
उत्तर
256x2– 32x + 1 = 0
Here a = 256, b = -32, c = 1
D = b2 - 4ac
= (-32)2 - 4 x 256 x 1
= 1024 - 1024
= 0
∵ x = `(-b ± sqrt("D"))/(2a)`
= `(-(-32) ± sqrt(0))/(2 xx 256)`
= `(32)/(512)`
= `(1)/(16)`
`x_1 = (1)/(16), x_2 = (1)/(16)`
Hence x = `(1)/(16), (1)/(16)`.
APPEARS IN
संबंधित प्रश्न
Solve the equation 4x2 – 5x – 3 = 0 and give your answer correct to two decimal places
Solve the following equation and give your answer correct to 3 significant figures:
5x2 – 3x – 4 = 0
Check whether the following is quadratic equation or not.
(x + 2)3 = x3 − 4
4(2x – 3)² – (2x – 3) – 14 = 0
Find the value of x, if a + 7=0; b + 10=0 and 12x2 = ax – b.
Solve the following equation for x and give, in the following case, your answer correct to 2 decimal places:
2x2 – 10x + 5 = 0
Which of the following are quadratic equation in x?
`x-6/x=3`
`sqrt7x^2-6x-13sqrt7=0`
The sum of the square of the 2 consecutive natural numbers is 481. Find the numbers.
If 3x2 – kx – 15 = (3x – 5)(x + 3), the value of k is ______.
