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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Solve the following : Find the amount a company should set aside at the end of every year if it wants to buy a machine expected to cost ₹1,00,000 at the end of 4 years - Mathematics and Statistics

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प्रश्न

Solve the following :

Find the amount a company should set aside at the end of every year if it wants to buy a machine expected to cost ₹1,00,000 at the end of 4 years and interest rate is 5% p. a. compounded annually. [(1.05)4 = 1.21550625]

बेरीज

उत्तर

Given, A = ₹1,00,000, n = 4 years, r = 5% p.a.

∴ i = `"r"/(100) = (5)/(100)`  = 0.05

Since, A = `"C"/"i"[(1 + "i")^"n" - 1]`

∴ 1,00,000 = `"C"/(0.05)[(1 + 0.05)^4 - 1]`

∴ 1,00,000  x 0.05 = C[(1.05)4 – 1]
∴ 5,000 = C(1.21550625 – 1)
∴ 5,000 = C x 0.21550625

∴ C = `(5000)/(0.21550625)`
∴ C = ₹23,201.18
∴ The company should set aside a sum of ₹23,201.18 in order to buy the machine.

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Annuity
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Insurance and Annuity - Miscellaneous Exercise 2 [पृष्ठ ३१]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] 12 Standard HSC Maharashtra State Board
पाठ 2 Insurance and Annuity
Miscellaneous Exercise 2 | Q 4.15 | पृष्ठ ३१

संबंधित प्रश्‍न

Find the present value of an ordinary annuity of ₹63,000 p.a. for 4 years at 14% p.a. compounded annually. [Given (1.14)−4 = 0.5921]


A lady plans to save for her daughter’s marriage. She wishes to accumulate a sum of ₹4,64,100 at the end of 4 years. What amount should she invest every year if she gets an interest of 10% p.a. compounded annually? [Given (1.1)4 = 1.4641]


Find the accumulated value of annuity due of ₹1,000 p.a. for 3 years at 10% p.a. compounded annually. [Given (1.1)3 = 1.331]


A person sets up a sinking fund in order to have ₹ 1,00,000 after 10 years. What amount should be deposited bi-annually in the account that pays him 5% p.a. compounded semi-annually? [Given (1.025)20 = 1.675]


Choose the correct alternative :

Amount of money today which is equal to series of payments in future is called


Choose the correct alternative :

Rental payment for an apartment is an example of


Fill in the blank :

The intervening time between payment of two successive installments is called as ___________.


Fill in the blank :

An annuity where payments continue forever is called __________.


State whether the following is True or False :

The future value of an annuity is the accumulated values of all installments.


Solve the following :

A company decides to set aside a certain amount at the end of every year to create a sinking fund that should amount to ₹9,28,200 in 4 years at 10% p.a. Find the amount to be set aside every year. [(1.1)4 = 1.4641]


Multiple choice questions:

In an ordinary annuity, payments or receipts occur at ______


Multiple choice questions:  

In annuity calculations, the interest is usually taken as ______


State whether the following statement is True or False:

The relation between accumulated value ‘A’ and present value ‘P’ is A = P(1+ i)n 


State whether the following statement is True or False:

The future value of an annuity is the accumulated values of all instalments


In ordinary annuity, payments or receipts occur at ______


The present value of an immediate annuity for 4 years at 10% p.a. compounded annually is ₹ 23,400. It’s accumulated value after 4 years would be ₹ ______


If payments of an annuity fall due at the beginning of every period, the series is called annuity ______


A company decides to set aside a certain sum at the end of each year to create a sinking fund, which should amount to ₹ 4 lakhs in 4 years at 10% p.a. Find the amount to be set aside each year?
[Given (1.1)4 = 1.4641]


For an annuity due, C = ₹ 2000, rate = 16% p.a. compounded quarterly for 1 year

∴ Rate of interest per quarter = `square/4` = 4

⇒ r = 4%

⇒ i = `square/100 = 4/100` = 0.04

n = Number of quarters

= 4 × 1

= `square`

⇒ P' = `(C(1 + i))/i [1 - (1 + i)^-n]`

⇒ P' = `(square(1 + square))/0.04 [1 - (square + 0.04)^-square]`

= `(2000(square))/square [1 - (square)^-4]`

= 50,000`(square)`[1 – 0.8548]

= ₹ 7,550.40


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