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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

A company decides to set aside a certain sum at the end of each year to create a sinking fund, which should amount to ₹ 4 lakhs in 4 years at 10% p.a. Find the amount to be set aside each year? [Give - Mathematics and Statistics

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प्रश्न

A company decides to set aside a certain sum at the end of each year to create a sinking fund, which should amount to ₹ 4 lakhs in 4 years at 10% p.a. Find the amount to be set aside each year?
[Given (1.1)4 = 1.4641]

बेरीज

उत्तर

Given, A = ₹ 4,00,000, n = 4 years, r = 10% p.a, i = `"r"/100 = 10/100` = 0.1

Now, A = `"C"/"i"[(1 + "i")^"n" - 1]`

∴ 4,00,000 = `"C"/0.1[(1 + 0.1)^4 - 1]`

∴ 4,00,000 × 0.1 = C[(1.1)4 − 1]

∴ 40,000 = C[1.4641 − 1]

∴ 40,000 = C(0.4641)

∴ C = `(40,000)/0.4641`

∴ C = ₹ 86,188.32

∴ The amount to be set aside each year is ₹ 2,00,000.

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Annuity
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2.2: Insurance and Annuity - Q.4

संबंधित प्रश्‍न

Find the accumulated value of annuity due of ₹1,000 p.a. for 3 years at 10% p.a. compounded annually. [Given (1.1)3 = 1.331]


An annuity immediate is to be paid for some years at 12% p.a. The present value of the annuity is ₹ 10,000 and the accumulated value is ₹ 20,000. Find the amount of each annuity payment


For an annuity immediate paid for 3 years with interest compounded at 10% p.a., the present value is ₹24,000. What will be the accumulated value after 3 years? [Given (1.1)3 = 1.331]


A person sets up a sinking fund in order to have ₹ 1,00,000 after 10 years. What amount should be deposited bi-annually in the account that pays him 5% p.a. compounded semi-annually? [Given (1.025)20 = 1.675]


Fill in the blank :

An annuity where payments continue forever is called __________.


Fill in the blank :

If payments of an annuity fall due at the beginning of every period, the series is called annuity __________.


Fill in the blank :

If payments of an annuity fall due at the end of every period, the series is called annuity __________.


State whether the following is True or False :

Annuity certain begins on a fixed date and ends when an event happens.


State whether the following is True or False :

Sinking fund is set aside at the beginning of a business.


Solve the following :

Find the least number of years for which an annuity of ₹3,000 per annum must run in order that its amount exceeds ₹60,000 at 10% compounded annually. [(1.1)11 = 2.8531, (1.1)12 = 3.1384]


Solve the following :

A person purchases a television by paying ₹20,000 in cash and promising to pay ₹1,000 at end of every month for the next 2 years. If money is worth 12% p. a. converted monthly, find the cash price of the television. [(1.01)–24 = 0.7875]


Solve the following :

Find the present value of an annuity immediate of ₹20,000 per annum for 3 years at 10% p.a. compounded annually. [(1.1)–3 = 0.7513]


Solve the following :

A company decides to set aside a certain amount at the end of every year to create a sinking fund that should amount to ₹9,28,200 in 4 years at 10% p.a. Find the amount to be set aside every year. [(1.1)4 = 1.4641]


Solve the following :

Find the future value after 2 years if an amount of ₹12,000 is invested at the end of every half year at 12% p. a. compounded half yearly. [(1.06)4 = 1.2625]


Multiple choice questions:

In an ordinary annuity, payments or receipts occur at ______


State whether the following statement is True or False:

A sinking fund is a fund established by financial organization


State whether the following statement is True or False:

The relation between accumulated value ‘A’ and present value ‘P’ is A = P(1+ i)n 


State whether the following statement is True or False:

An annuity where payments continue forever is called perpetuity


A 35-year old person takes a policy for ₹ 1,00,000 for a period of 20 years. The rate of premium is ₹ 76 and the average rate of bonus is ₹ 7 per thousand p.a. If he dies after paying 10 annual premiums, what amount will his nominee receive?


For annuity due,

C = ₹ 20,000, n = 3, I = 0.1, (1.1)–3 = 0.7513

Therefore, P = `square/0.1 xx [1 - (1 + 0.1)^square]`

= 2,00,000 [1 – 0.7513]

= ₹ `square`


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