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प्रश्न
For annuity due,
C = ₹ 20,000, n = 3, I = 0.1, (1.1)–3 = 0.7513
Therefore, P = `square/0.1 xx [1 - (1 + 0.1)^square]`
= 2,00,000 [1 – 0.7513]
= ₹ `square`
उत्तर
For annuity due,
C = ₹ 20,000, n = 3, I = 0.1, (1.1)–3 = 0.7513
Therefore, P = `(20,000)/0.1 xx [1 - (1 + 0.1)^-3]`
= 2,00,000 [1 – 0.7513]
= ₹ 49,740
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