Advertisements
Advertisements
प्रश्न
Solve the following pairs of equations:
`(x + y)/(xy)` = 2
`(x - y)/(xy)` = 6
उत्तर
`(x + y)/(xy)` = 2
⇒ x + y = 2xy ....(i)
`(x - y)/(xy)` = 6
⇒ x - y = 6xy ....(ii)
Adding eqns. (i) and (ii), we get
2x = 8xy
⇒ y = `(1)/(4)`
Substituting the value of y in eqn. (i), we get
`x + (1)/(4) = 2x xx (1)/(4)`
⇒ `(4x + 1)/(4) = x/(2)`
⇒ 8x + 2 = 4x
⇒ 4x = -2
⇒ x = `-(1)/(2)`
Thus, the solution set is `(-1/2, 1/4)`.
APPEARS IN
संबंधित प्रश्न
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
`[5y]/2 - x/3 = 8`
`y/2 + [5x]/3 = 12`
The value of expression mx - ny is 3 when x = 5 and y = 6. And its value is 8 when x = 6 and y = 5. Find the values of m and n.
Solve the following simultaneous equations :
6x + 3y = 7xy
3x + 9y = 11xy
Solve the following pairs of equations:
y - x = 0.8
`(13)/(2(x + y)) = 1`
Solve the following pairs of equations:
`(5)/(x + y) - (2)/(x - y)` = -1
`(15)/(x + y) + (7)/(x - y)` = 10.
Solve the following pairs of equations:
`(xy)/(x + y) = (6)/(5)`
`(xy)/(y - x)` = 6
Where x + y ≠ 0 and y - x ≠ 0
Can the following equations hold simultaneously?
7y - 3x = 7
5y - 11x = 87
5x + 4y = 43
If yes, find the value of x and y.
A person goes 8 km downstream in 40 minutes and returns in 1 hour. Determine the speed of the person in still water and the speed of the stream.
Sunil and Kafeel both have some oranges. If Sunil gives 2 oranges to Kafeel, then Kafeel will have thrice as many as Sunil. And if Kafeel gives 2 oranges to Sunil, then they will have the same numbers of oranges. How many oranges does each have?
Two mobiles S1 and S2 are sold for Rs. 10,490 making 4% profit on S1 and 6% on S2. If the two mobiles are sold for Rs.10,510, a profit of 6% is made on S1 and 4% on S2. Find the cost price of both the mobiles.
