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Solve: (x – 4)(x – 2)(x- 7)(x + 1) = 16 - Mathematics

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प्रश्न

Solve: (x – 4)(x – 2)(x- 7)(x + 1) = 16

बेरीज

उत्तर

(x – 4)(x – 7) (x – 2)(x + 1) = 16

⇒ (x – 4)(x – 2)(x – 7)(x + 1) = 16

⇒ (x2 – 6x + 8)(x2 – 6x – 7) = 16

Let x2 – 6x = y

(y + 8)(y – 7) = 16

⇒ y2 – 7y + 8y – 56 – 16 = 0

⇒ y2 + y – 72 = 0

⇒ (y + 9)(y – 8) = 0

y + 9 = 0

x2 – 6x + 9 = 0

(x – 3)2 = 0

x = 3, 3

or

y – 8 = 0

x2 – 6x – 8 = 0

x = `(6 +- sqrt(36 - 4(1)(- 8)))/(2(1))`

= `(6 +- sqrt(36 + 32))/2`

= `(6 + sqrt(68))/2`

= `(6 +- 2sqrt(17))/2`

= `2 ((3 +-  sqrt(17)))/2`

= `3 + sqrt(17)`

Roots are `3, 3, 3 +- sqrt(17)`

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Theory of Equations - Exercise 3.4 [पृष्ठ ११८]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 3 Theory of Equations
Exercise 3.4 | Q 1. (ii) | पृष्ठ ११८
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