Advertisements
Advertisements
प्रश्न
Suppose that the particle is an electron projected with velocity vx = 2.0 × 106 m s−1. If E between the plates separated by 0.5 cm is 9.1 × 102 N/C, where will the electron strike the upper plate? (|e| = 1.6 × 10−19 C, me = 9.1 × 10−31 kg)
उत्तर
Velocity of the particle, vx = 2.0 × 106 m/s
Separation of the two plates, d = 0.5 cm = 0.005 m
Electric field between the two plates, E = 9.1 × 102 N/C
Charge on an electron, q = 1.6 × 10−19 C
Mass of an electron, me = 9.1 × 10−31 kg
Let the electron strike the upper plate at the end of plate L, when deflection is s.
Therefore,
`"s" = ("qEL"^2)/(2"mv"_"x"^2)`
`"L" = sqrt((2"dmv"_"x"^2)/("qE"))`
= `sqrt((2 xx 0.005 xx 9.1 xx 10^-31 xx (2.0 xx 10^6)^2)/(1.6 xx 10^-10 xx 9.1 xx 10^2))`
= `sqrt(0.025 xx 10^-2)`
= `sqrt(2.5 xx 10^-4)`
= `1.6xx10^-2` m
= 1.6 cm
Therefore, the electron will strike the upper plate after travelling 1.6 cm.
APPEARS IN
संबंधित प्रश्न
Find the dimensional formula of ε0.
At what separation should two equal charges, 1.0 C each, be placed, so that the force between them equals the weight of a 50 kg person?
Suppose the second charge in the previous problem is −1.0 × 10−6 C. Locate the position where a third charge will not experience a net force.
Two insulating small spheres are rubbed against each other and placed 1 cm apart. If they attract each other with a force of 0.1 N, how many electrons were transferred from one sphere to the other during rubbing?
NaCl molecule is bound due to the electric force between the sodium and the chlorine ions when one electron of sodium is transferred to chlorine. Taking the separation between the ions to be 2.75 × 10−8 cm, find the force of attraction between them. State the assumptions (if any) that you have made.
Find the ratio of the electrical and gravitational forces between two protons.
Find the speed of the electron in the ground state of a hydrogen atom. The description of ground state is given in the previous problem.
A particle A with a charge of 2.0 × 10−6 C is held fixed on a horizontal table. A second charged particle of mass 80 g stays in equilibrium on the table at a distance of 10 cm from the first charge. The coefficient of friction between the table and this second particle is μ = 0.2. Find the range within which the charge of this second particle may lie.
Repeat the previous problem if the particle C is displaced through a distance x along the line AB.
Write a short note on superposition principle.
Polarised dielectric is equivalent to ______.
Two point charges +3 µC and +8 µC repel each other with a force of 40 N. If a charge of -5 µC is added to each of them, then force between them will become ______.
Two positive charges ______.
A spring of spring constant 5 × 103 N/m is stretched initially by 5 cm from the unstretched position. Then the work required to stretch it further by another 5 cm is:
Two charge – 10c and + 10 c are placed 10 cm apart. Potential at centre of the line joining the two charge is:-
The capacity of an isolate conducting sphere of radius R is proportional to
Two charges q and – 3q are placed fixed on x-axis separated by distance ‘d’. Where should a third charge 2q be placed such that it will not experience any force?
Which of the following statements about nuclear forces is not true?
Two point charges +2 C and +6 C repel each other with a force of 12 N. If a charge of -4 C is given to each of these charges, then the force now is ______.
