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सी.आई.एस.सी.ई.आयसीएसई ICSE Class 7

The adjacent sides of a parallelogram are 15 cm and 10 cm. If the distance between the longer sides is 6 cm, find the distance between the shorter sides. - Mathematics

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प्रश्न

The adjacent sides of a parallelogram are 15 cm and 10 cm. If the distance between the longer sides is 6 cm, find the distance between the shorter sides.

बेरीज

उत्तर

In parallelogram ABCD

AB = DC = 15 cm

BC = AD = 10 cm

Distance between longer sides AB and DC is 6 cm

i.e., perpendicular DL = 6 cm

DM ⊥ BC

Area of parallelogram = Base × Altitude

= AB × DL = 15 × 6 = 90 cm2

Again let DM = x cm

∴ Area of parallelogram ABCD = BC × DM 

= 10 × x = 10x cm2

∴ 10x cm2 = 90 cm2

⇒ x = `90/10` = 9 cm

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Concept of Measurement Using a Basic Unit Area of a Square, Rectangle, Triangle, Parallelogram and Circle, Rings and Combined Figures.
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पाठ 20: Mensuration - Exercise 20 (B)

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सेलिना Concise Mathematics [English] Class 7 ICSE
पाठ 20 Mensuration
Exercise 20 (B) | Q 14
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