Advertisements
Advertisements
प्रश्न
The amount of heat energy required to convert 1 kg of ice at – 10℃ to water at 100℃ is 7,77,000 J. Calculate the specific latent heat of ice. Specific heat capacity of ice = 2100 J kg-1K-1, Specific heat capacity of water = 4200 J kg-1 K-1.
उत्तर
Amount of heat energy gained by 1 kg of ice at −10°C to raise its temperature to 0°C = 1 × 2100 × 10 = 21000 J
Amount of heat energy gained by 1 kg of ice at 0°C to convert into water at 0°C = L
Amount of heat energy gained when temperature of 1 kg of water at 0°C rises to 100°C = 1 × 4200 × 100 = 420000 J
Total amount of heat energy gained = 21000 + 420000 + L = 441000 + L.
Given that total amount of heat gained is = 777000 J.
So,
441000 + L = 777000.
L = 777000 − 441000.
L = 336000 J Kg-1
APPEARS IN
संबंधित प्रश्न
Name the law on which principle of Calorimetry is based
Calculate the amount of heat energy required to raise the temperature of 100 g of copper from 20°C to 70°C. specific heat capacity of copper = `390 J kg^-1 K^-1`.
1300 J of heat energy is supplied to raise the temperature of 6.5 kg of lead from 20° C to 40°C. Calculate the specific heat capacity of lead.
10g of ice at 0℃ absorbs 5460 J of heat energy to melt and change to water at 50℃. Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200 J kg-1 K-1.
Express -400C on the Fahrenheit scale.
100 g of ice at -10°C is heated. It is converted into steam. Calculate the quantity of heat which it has consumed. (Sp. heat of ice = 2100J/kg°C, sp. heat of water= 4200 J/kgK, sp. heat of water = 42000 J/kgK, sp. latent heat of ice = 2260000 J/kg).
Why does the heat supplied to a substance during its change of state not cause any rise in its temperature?
Explain briefly, how you would determine the specific heat capacity of a liquid?
A Bunsen burner raises the temperature of 500g of water from 10°C to 100°C in 5 minutes. What heat is supplied per second?
