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The Area of an Equilateral Triangle is 49 √ 3 Cm2 . Taking Each Angular Point as Centre, Circles Are Drawn with Radius Equal to Half the Length of the Side of the - Mathematics

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प्रश्न

The area of an equilateral triangle is `49sqrt(3)` cm2 . Taking each angular point as centre, circles are drawn with radius equal to half the length of the side of the triangle. Find the area of the triangle not included in the circles. [Take π = 1.73] 

बेरीज

उत्तर

Area of equilateral triangle`= 49 sqrt(3)`

`=> sqrt(3)/4xx("Side")^2 = 49sqrt(3)`

⇒ (Side)2 = 72 × 22

⇒ Side = 14 cm

Radius of the circle = Half of the side of the triangle = 7 cm
Area of triangle not included in the circle = Area of triangle − Area of 3 sectors having central angle 60

`=49sqrt(3) - 3xx60^circ/360^circxx22/7xx7xx7`

= 84.77 -  77 

= 7.77 cm2

Hence, the required area is 7.77 cm2  

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पाठ 18: Area of Circle, Sector and Segment - Exercise 18A [पृष्ठ ८३५]

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आर एस अग्रवाल Mathematics [English] Class 10
पाठ 18 Area of Circle, Sector and Segment
Exercise 18A | Q 52 | पृष्ठ ८३५

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