Advertisements
Advertisements
प्रश्न
The radius of a circular garden is 100 m. There is a road 10 m wide, running all around it. Find the area of the road and the cost of levelling it at Rs 20 per m2. [Use π = 3.14]
उत्तर
Area of the road = Area of outer circle − Area of inner circle
= πR2 - πr2
= π [(110)2 - (100)2]
= 3.14 × 2100
= 6594 m2
Cost of levelling the road = Area of the road ⨯ Rate
= 6594 ⨯ 20
= Rs 131880
APPEARS IN
संबंधित प्रश्न
In Fig. 7, are shown two arcs PAQ and PBQ. Arc PAQ is a part of circle with centre O and radius OP while arc PBQ is a semi-circle drawn on PQ ad diameter with centre M. If OP = PQ = 10 cm show that area of shaded region is `25(sqrt3-pi/6)cm^2`.
The length of a chain used as the boundary of a semicircular park is 108 m. Find the area of the park.
Find the curved surface area , the total surface area and the volume of a cone if its :
Height = 8 cm , diameter = 12 cm
Find the area grazed by a horse tied with a 11. 2 m rope to a corner of a field measuring 25m by 15 m.
Find the diameter of the sphere for the following :
Volume = `72pi "cm"^3`
Find the diameter of the sphere for the following :
Surface Area = `576pi`cm2
The sum of the circumference and diameter of a circle is 116 cm. Find its radius.
The circumference of a circle exceeds its diameter by 18 cm. find the radius of the circle.
Find the area and perimeter of the circles with following: Radius = 2.8cm
The area of a square is 100 cm2. The circumference (in cm) of the largest circle cut of it is ______.
