Advertisements
Advertisements
Question
The radius of a circular garden is 100 m. There is a road 10 m wide, running all around it. Find the area of the road and the cost of levelling it at Rs 20 per m2. [Use π = 3.14]
Solution
Area of the road = Area of outer circle − Area of inner circle
= πR2 - πr2
= π [(110)2 - (100)2]
= 3.14 × 2100
= 6594 m2
Cost of levelling the road = Area of the road ⨯ Rate
= 6594 ⨯ 20
= Rs 131880
APPEARS IN
RELATED QUESTIONS
The area of circle, inscribed in equilateral triangle is 154 cms2. Find the perimeter of
triangle.
Four equal circles, each of radius 5 cm touch each other as shown in fig. Find the area included etween them.
Diagonal of a square is 20 cm. Find the length and perimeter of the square.
A canvas tent is in the shape of a cylinder surmounted by a conical roof. The common diameter of the cone and the cylinder is 14 m. The height of the cylindrical part is 8 m and the height of the conical roof is 4 m. Find the area of the canvas used to make the tent.
Each wheel of a car is of diameter 80 cm. How many completer revolutions does each wheel make in 10 minutes when the car is traveling at a speed of 66 km per hour?
The diameters of the front and the rear wheels of a tractor are 63 cm and 1.54 m respectively. The rear wheel is rotating at `24 6/11` revolutions per minute. Find:
(i) the revolutions per minute made by the front wheel.
(ii) the distance traveled bu the tractor in 40 minutes.
If the circumference of a circle is 176 cm, find its radius.
The wheel of a car makes 10 revolutions per second. If its diameter is 70cm, find the speed of the car in km per hr.
The radius of a circular plot is 7.7 metres. How much will it cost to fence the plot with 3 rounds of wire at the rate of 50 rupees per metre?
A race track is in the form of a circular ring whose outer and inner circumferences are 396 m and 352 m respectively. The width of the track is ____________.