Advertisements
Advertisements
प्रश्न
The area of a trapezium become 4 times if its height gets doubled.
पर्याय
True
False
उत्तर
This statement is False.
Explanation:
We know that,
Area of a trapezium = `1/2 (a + b) xx h`
Where, a and b are the lengths of parallel sides and h is the altitude (height).
Now, if the height gets doubled, then
Area of trapezium = `1/2(a + b) xx 2h = 2(1/2(a + b) xx h)`
Hence, the area is doubled.
So, the statement is false.
APPEARS IN
संबंधित प्रश्न
Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.
Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of the octagonal surface.
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 150 cm and 30 dm, altitude = 9 dm.
The area of a trapezium is 960 cm2. If the parallel sides are 34 cm and 46 cm, find the distance between them.
The area of a trapezium is 91 cm2 and its height is 7 cm. If one of the parallel sides is longer than the other by 8 cm, find the two parallel sides.
The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.
Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.
The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape.
If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.
The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.
Find the area of the following fields. All dimensions are in metres.